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(x^2/5)^2-5x=0
We add all the numbers together, and all the variables
-5x+(x^2/5)^2=0
We multiply all the terms by the denominator
-5x*5)^2+(x^2=0
Wy multiply elements
-25x^2=0
a = -25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-25)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-50}=0$
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